COMEDK · Chemistry · 19. Chemical Kinetics
For the reaction \(\mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{NO}_{(\mathrm{g})} \rightarrow 2 \mathrm{NOCl}_{(\mathrm{g})}\), the following data was obtained:
| Experiment No. | Initial concentration of \(Cl_2\) (M) | Initial concentration of NO (M) | Initial reaction rate (M/min) |
|---|---|---|---|
| I | 0.15 | 0.15 | 0.60 |
| II | 0.30 | 0.15 | 1.20 |
| III | 0.15 | 0.30 | 2.40 |
| IV | 0.25 | 0.25 | 2.78 |
Identify the order of the reaction with respect to \(\mathrm{Cl}_2, \mathrm{NO}\) and the value of Rate constant.
- A \(\text { Order with respect to } \mathrm{Cl}_2=0 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=8.0 \mathrm{~min}^{-1}\)
- B \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=26.66 \mathrm{~mol}^{-1} \mathrm{Lmin}^{-1}\)
- C \(\text { Order with respect to } \mathrm{Cl}_2=2 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=355.5 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)
- D \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=2 \quad \mathrm{k}=177.7 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)
Answer & Solution
Correct Answer
(D) \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=2 \quad \mathrm{k}=177.7 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)
Step-by-step Solution
Detailed explanation
The rate law for the reaction is given by \(Rate = k[Cl_2]^x [NO]^y\). Using data from Experiment I and II: \(0.60 = k(0.15)^x (0.15)^y\) \(1.20 = k(0.30)^x (0.15)^y\) Dividing the two equations:…
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