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COMEDK · Chemistry · 19. Chemical Kinetics

For the reaction \(\mathrm{Cl}_{2(\mathrm{~g})}+2 \mathrm{NO}_{(\mathrm{g})} \rightarrow 2 \mathrm{NOCl}_{(\mathrm{g})}\), the following data was obtained:

Experiment No.Initial concentration of \(Cl_2\) (M)Initial concentration of NO (M)Initial reaction rate (M/min)
I0.150.150.60
II0.300.151.20
III0.150.302.40
IV0.250.252.78

Identify the order of the reaction with respect to \(\mathrm{Cl}_2, \mathrm{NO}\) and the value of Rate constant.

  1. A \(\text { Order with respect to } \mathrm{Cl}_2=0 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=8.0 \mathrm{~min}^{-1}\)
  2. B \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=26.66 \mathrm{~mol}^{-1} \mathrm{Lmin}^{-1}\)
  3. C \(\text { Order with respect to } \mathrm{Cl}_2=2 \quad \text { Order with respect to } \mathrm{NO}=1 \quad \mathrm{k}=355.5 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)
  4. D \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=2 \quad \mathrm{k}=177.7 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\text { Order with respect to } \mathrm{Cl}_2=1 \quad \text { Order with respect to } \mathrm{NO}=2 \quad \mathrm{k}=177.7 \mathrm{~mol}^{-2} \mathrm{~L}^2 \mathrm{~min}^{-1}\)

Step-by-step Solution

Detailed explanation

The rate law for the reaction is given by \(Rate = k[Cl_2]^x [NO]^y\). Using data from Experiment I and II: \(0.60 = k(0.15)^x (0.15)^y\) \(1.20 = k(0.30)^x (0.15)^y\) Dividing the two equations:…