COMEDK · Chemistry · 19. Chemical Kinetics
For the reaction, \(\mathrm{A}+3 \mathrm{~B} \rightarrow 2 \mathrm{C}+\mathrm{D}\), the concentration of \(\mathrm{A}\) changes from 0.0150 to 0.0125 in 1 minute. The rate of formation of \(\mathrm{C}\) in \(\mathrm{mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\) is:
- A \(6.32 \times 10^{-5}\)
- B \(3.26 \times 10^{-5}\)
- C \(8.33 \times 10^{-5}\)
- D \(2.5 \times 10^{-5}\)
Answer & Solution
Correct Answer
(C) \(8.33 \times 10^{-5}\)
Step-by-step Solution
Detailed explanation
The rate of reaction with respect to reactant A is given by the expression: Rate \(= -\dfrac{d[A]}{dt} = -\dfrac{[A]_2 - [A]_1}{t_2 - t_1}\) Given \([A]_1 = 0.0150 \text{ mol L}^{-1}\), \([A]_2 = 0.0125 \text{ mol L}^{-1}\), and…
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