COMEDK · Chemistry · 6. Thermodynamics (C)
For a reaction to be spontaneous at all temperatures
- A \(\Delta G\) and \(\Delta H\) should be negative
- B \(\Delta G\) and \(\Delta H\) should be positive
- C \(\Delta G=\Delta S=0\)
- D \(\Delta H < \Delta G\)
Answer & Solution
Correct Answer
(A) \(\Delta G\) and \(\Delta H\) should be negative
Step-by-step Solution
Detailed explanation
For a reaction to be spontaneous at all temperature \(\Delta G\) should be negative. As we know \(\Delta G=\Delta H-T \Delta S\) \[ =-\text { ve }-T(+\text { ve })=-\text { ve } \] \(\therefore \Delta G\) and \(\Delta H\) should be negative.
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