COMEDK · Chemistry · 19. Chemical Kinetics

For a reaction \(A+B \longrightarrow C+D\), if
concentration of \(A\) is doubled without altering that of \(B\), rate doubles. If concentration of \(B\) is increased nine-times without altering that of \(A\), rate triples. Order of the reaction is

A \(2\)
B \(1\)
C \(1 \frac{1}{2}\)
D \(1 \frac{1}{3}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(1 \frac{1}{2}\)

Step-by-step Solution

Detailed explanation

If [A] double's then, \(r_{l}=2 r\) If \([B]\) increased 9 times then, \(r_{2}=3 r\) \(\therefore\) Order w.r.t. \(A\) is 1 and order w.r.t \(B\) is \(\frac{1}{2}\). \(\therefore\) Order of reaction \(=1+\frac{1}{2}=1 \frac{1}{2}\).

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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For a reaction \(A+B \longrightarrow C+D\), ifconcentration of \(A\) is doubled without altering that of \(B\), rate doubles. If concentration of \(B\) is increased nine-times without altering that of \(A\), rate triples. Order of the reaction is

Step-by-step Solution

For a reaction \(A+B \longrightarrow C+D\), if
concentration of \(A\) is doubled without altering that of \(B\), rate doubles. If concentration of \(B\) is increased nine-times without altering that of \(A\), rate triples. Order of the reaction is