COMEDK · Chemistry · 19. Chemical Kinetics
For a given reaction of the type \(\dfrac{3}{5} X(a q) \rightarrow \dfrac{1}{2} Y(a q)+Z(g)\), the correct expression for the rate of disappearance of \(X\) with reference to \(Y\) is \(\qquad\)
- A \(-d \dfrac{[X]}{d t}=+\dfrac{5}{6} d \dfrac{[Y]}{d t}\)
- B \(-d \dfrac{[X]}{d t}=+\dfrac{3}{10} d \dfrac{[Y]}{d t}\)
- C \(-d \dfrac{[X]}{d t}=+\dfrac{6}{5} d \dfrac{[Y]}{d t}\)
- D \(-d \dfrac{[X]}{d t}=d \dfrac{[Y]^{1 / 2}}{d t}\)
Answer & Solution
Correct Answer
(C) \(-d \dfrac{[X]}{d t}=+\dfrac{6}{5} d \dfrac{[Y]}{d t}\)
Step-by-step Solution
Detailed explanation
For a general chemical reaction \(aA + bB \rightarrow cC + dD\), the rate of reaction is given by \(-\dfrac{1}{a} \dfrac{d[A]}{dt} = -\dfrac{1}{b} \dfrac{d[B]}{dt} = \dfrac{1}{c} \dfrac{d[C]}{dt} = \dfrac{1}{d} \dfrac{d[D]}{dt}\). Given the reaction…
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