COMEDK · Chemistry · 18. Electrochemistry
For a cell reaction, \(A(s)+B^{2+}(a q) \longrightarrow A^{2+}(a q)+B(s)\); the standard emf of the cell is \(0.295 \mathrm{~V}\) at \(25^{\circ} \mathrm{C}\). The equilibrium constant at \(25^{\circ} \mathrm{C}\) will be
- A \(2.95 \times 10^{-10}\)
- B 10
- C \(1 \times 10^{10}\)
- D \(2.95 \times 10^{-2}\)
Answer & Solution
Correct Answer
(C) \(1 \times 10^{10}\)
Step-by-step Solution
Detailed explanation
The cell reaction is \(A(s) + B^{2+}(aq) \rightarrow A^{2+}(aq) + B(s)\). The number of electrons transferred in the reaction is \(n = 2\). The relationship between the standard cell potential \(E^{\circ}_{cell}\) and the equilibrium constant \(K_{eq}\) is given by the Nernst…
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