COMEDK · Chemistry · 12. p Block Elements (Group 13 & 14)
Find the correct matches of the substances, given in Column I, from their characteristic properties given in Column II.
| S.No. | Column I | S.No. | Column II |
|---|---|---|---|
| W | \( \mathrm{Tl} \) | A | Decomposes steam to form its dioxide and dihydrogen gas. |
| X | \( \mathrm{CCl}_4 \) | B | Consists of twenty 6 -membered rings and twelve 5 membered rings. |
| Y | \(\mathrm{Tin}\) | C | +3 oxidation state is highly oxidising. |
| Z | \( \mathrm{C_{60}} \) | D | Electron precise species, neither acts as electron donor nor as electron acceptor. |
- A \(\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{D} \quad \mathrm{Y}=\mathrm{A} \quad \mathrm{Z}=\mathrm{B}\)
- B \(\mathrm{W}=\mathrm{D} \quad \mathrm{X}=\mathrm{C} \quad \mathrm{Y}=\mathrm{B} \quad \mathrm{Z}=\mathrm{A}\)
- C \(\mathrm{W}=\mathrm{B} \quad \mathrm{X}=\mathrm{D} \quad \mathrm{Y}=\mathrm{C} \quad \mathrm{Z}=\mathrm{A}\)
- D \(\mathrm{W}=\mathrm{D} \quad \mathrm{X}=\mathrm{C} \quad \mathrm{Y}=\mathrm{A} \quad \mathrm{Z}=\mathrm{B}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{W}=\mathrm{C} \quad \mathrm{X}=\mathrm{D} \quad \mathrm{Y}=\mathrm{A} \quad \mathrm{Z}=\mathrm{B}\)
Step-by-step Solution
Detailed explanation
Correct option is A.
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