COMEDK · Chemistry · 23. d and f Block Elements
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\(\begin{array}{|l|l|l|l|} \hline \text{A} & \mathrm{Cr}_2 \mathrm{O}_7^{2-} & \mathrm{P} & \text{is predominantly a basic compound.} \\ \hline \text{B} & \mathrm{FeCr}_2 \mathrm{O}_4 & \mathrm{Q} & \text{is predominantly an acidic compound.} \\ \hline \text{C} & \mathrm{CrO}_3 & \mathrm{R} & \text{forms yellow chromate on reaction with } \mathrm{Na}_2 \mathrm{CO}_3 \text{ in air.} \\ \hline \text{D} & \mathrm{CrO} & \mathrm{S} & \text{is interconvertible with } \mathrm{MO}_4^{2-} \text{ depending on the pH of the medium.} \\ \hline \end{array}\)
- A \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q}\)
- B \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{P}\)
- C \(\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}\)
- D \(\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}\)
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Detailed explanation
The dichromate ion \(\mathrm{Cr}_2 \mathrm{O}_7^{2-}\) exists in equilibrium with the chromate ion \(\mathrm{CrO}_4^{2-}\) depending on the pH of the medium, where…
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