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COMEDK · Chemistry · 22. p Block Elements (Group 15, 16, 17 & 18)

Excess of \(\mathrm{PCl}_{5}\) reacts with con(c) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) giving

  1. A chlorosulphonic acid
  2. B thionyl chloride
  3. C sulphuryl chloride
  4. D sulphurous acid
Verified Solution

Answer & Solution

Correct Answer

(C) sulphuryl chloride

Step-by-step Solution

Detailed explanation

\(\mathrm{H}_{2}\mathrm{SO}_{4} + 2\mathrm{PCl}_{5} \rightarrow \mathrm{SO}_{2}\mathrm{Cl}_{2} + 2\mathrm{POCl}_{3} + 2\mathrm{HCl}\) Sulphuryl chloride