COMEDK · Chemistry · 28. Carboxylic Acid Derivatives
Ethyl benzoate reacts with \(\mathrm{PCl}_{5}\) to give
- A \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\mathrm{POCl}_{3}+\mathrm{HCl}\)
- B \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\mathrm{POCl}_{3}\)
- C \(\mathrm{CH}_{3} \mathrm{COCl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\mathrm{POCl}_{3}\)
- D \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}+\mathrm{POCl}_{3}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}+\mathrm{POCl}_{3}\)
Step-by-step Solution
Detailed explanation
Ethyl benzoate reacts with \(\mathrm{PCl}_{5}\) to give \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\), \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}\) and \(\mathrm{POCl}_{3}\).
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