COMEDK · Chemistry · 19. Chemical Kinetics
During a chemical reaction \(\mathrm{X} \rightarrow \mathrm{Y}\), the rates of reaction starting with initial concentrations of X as \(4.0 \times 10^{-3} \mathrm{M}\) and \(2.0 \times 10^{-3} \mathrm{M}\) are \(4.8 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} / \mathrm{s}\) and \(1.2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} / \mathrm{s}\) respectively. What is the order of reaction with respect to X ?
- A \(1.5\)
- B \(2\)
- C \(1\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
The rate law for the reaction \(\mathrm{X} \rightarrow \mathrm{Y}\) is given by \(r = k[X]^{n}\), where \(n\) is the order of the reaction. For the first condition: \(4.8 \times 10^{-4} = k(4.0 \times 10^{-3})^{n}\) (Equation 1) For the second condition:…
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