COMEDK · Chemistry · 19. Chemical Kinetics
Decomposition of \(\mathrm{NH}_{3}\) on the surface of platinum has a rate constant of \(2.5 \times 10^{-4} \mathrm{~mol} \mathrm{dm^{-3 } \mathrm { s } ^ { - 1 } \text { at } 3 5 0 \mathrm { K } \text { . The order of }}\) the reaction is
- A 0
- B 1
- C \(1 / 2\)
- D 2
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
Unit of rate constant of \(n\)th order \[ (k)=\left(\frac{\mathrm{mol}}{\mathrm{dm}^{3}}\right)^{1-n} \mathrm{~s}^{-1} \] for zero order \((n)=0\) \[ \therefore \quad k=\operatorname{mol~dm}{ }^{-3} \mathrm{~s}^{-1} \] \(\therefore\) The order of reaction is 1st.
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