COMEDK · Chemistry · 18. Electrochemistry
\(\mathrm{Cu}^{+}\) undergoes disproportionation, according to the equation,
\(
2 \mathrm{Cu}^{+} \rightleftharpoons \mathrm{Cu}^{2+}+\mathrm{Cu}
\)
The \(\mathrm{E}^{\circ}\) value for the reaction is:
\([\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{\mathrm{o}}=0.34 \mathrm{~V} \text { and } \mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}^{+}}^{\mathrm{O}}=0.15 \mathrm{~V}]\)
- A \(-0.49\) V
- B \(+0.38\) V
- C \(+0.49\) V
- D \(-0.56\) V
Answer & Solution
Correct Answer
(B) \(+0.38\) V
Step-by-step Solution
Detailed explanation
The given disproportionation reaction is \(2 \mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+} + \mathrm{Cu}\). This reaction can be split into two half-reactions: 1) Oxidation: \(\mathrm{Cu}^{+} \rightarrow \mathrm{Cu}^{2+} + e^{-}\) (where…
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