COMEDK · Chemistry · 18. Electrochemistry
\(\mathrm{Cu}(s)+\mathrm{Sn}^{2+}(0.01 \mathrm{M}) \longrightarrow \mathrm{Cu}^{2+}(0.1 \mathrm{M})+\mathrm{Sn}(s)\)
The gibbs free energy change for above mention reaction at NTP is \(x \times 10^{-1} \mathrm{~kJ} / \mathrm{mol}\). The value of \(x\) is \(\qquad\) [Nearest integer]
\(\left[\right.\) Given \(E_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^{\circ}=0.34 \mathrm{~V}, E_{\mathrm{Sn}^{2+} / / \mathrm{sn}}^{\circ}=-0.14 \mathrm{~V}\) \(F=96500 \mathrm{C} / \mathrm{mol}]\)
- A 983
- B 883
- C 1083
- D 863
Answer & Solution
Correct Answer
(A) 983
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