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COMEDK · Chemistry · 7. Chemical Equilibrium

Consider the following equilibrium,
\(\begin{aligned}
& 2 \mathrm{No}(g) \rightleftharpoons \mathrm{N}_2+\mathrm{O}_2 ; K_{\mathrm{G}_1}=2.4 \times 10^{20} \\
& \mathrm{No}(g)+\frac{1}{2} \mathrm{Br}_2(\mathrm{~g}) \rightleftharpoons \mathrm{NoBr}(g) ; K_{C_2}=1.4
\end{aligned}\)
Calculate \(K_C\) for the reaction,
\(\frac{1}{2} \mathrm{~N}_2(g)+\frac{1}{2} \mathrm{O}_2(g)+\frac{1}{2} \mathrm{Br}_2(g) \rightleftharpoons \mathrm{NOBr}(g)\)

  1. A \(8.96 \times 10^{-11}\)
  2. B \(9.48 \times 10^{-\theta}\)
  3. C \(8.08 \times 10^{-12}\)
  4. D \(8.96 \times 10^{11}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(8.96 \times 10^{-11}\)

Step-by-step Solution

Detailed explanation

For, \(2 \mathrm{NO}(\mathrm{g}) \rightleftharpoons \mathrm{N}_2+\mathrm{O}_2\) \(\mathrm{K}_{\mathrm{C}_1}=\frac{\left[\mathrm{N}_2\right]\left[\mathrm{O}_2\right]}{[\mathrm{NO}]^2}=2.4 \times 10^{20}\) For,…
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