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COMEDK · Chemistry · 18. Electrochemistry

Calculate the molar conductance of \(0.025 \mathrm{M}\) aqueous solution of calcium chloride at \(25^{\circ} \mathrm{C}\). The specific conductance of calcium chloride is \(12.04 \times 10^{-2} \mathrm{Sm}^{-1}\)

  1. A \(4.816 \times 10^{-5} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\)
  2. B \(3.816 \times 10^{-5} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\)
  3. C \(381.6 \times 10^{-5} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\)
  4. D \(481.6 \times 10^{-5} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(481.6 \times 10^{-5} \mathrm{Sm}^2 \mathrm{~mol}^{-1}\)

Step-by-step Solution

Detailed explanation

The molar conductance \(\Lambda_m\) is given by the formula \(\Lambda_m = \dfrac{\kappa}{C}\), where \(\kappa\) is the specific conductance and \(C\) is the molar concentration. Given: \(\kappa = 12.04 \times 10^{-2} \text{ S m}^{-1}\)…