Based on Valence Bond Theory, match the complexes listed in Column I with the number of unpaired electrons on the central metal ion, given in Column II

No.	Complex ions	No.	Number of unpaired electrons
A	\([FeF_6]^{3-}\)	P	0
B	\([Fe(CN)_6]^{4-}\)	Q	1
C	\([Fe(H_2O)_6]^{2+}\)	R	5
D	\([Fe(CN)_6]^{3-}\)	S	4

The Paschen series of hydrogen spectrum lies in which region?

Match the coordination compounds in Column I having the given type of hybridisation of \(\mathrm{M}^{\mathrm{n}+}\) ion and magnetic moment as given in Column II.
\(\begin{array}{|l|l|l|l|} \hline & \text { Coordination compounds. } & & \text { Hybridisation \& Magnetic nature. } \\ \hline \text { A } & \mathrm{Ni}(\mathrm{CO})_4 & \text { P } & \mathrm{sp}^3, \quad \mu=5.92 \mathrm{BM} \\ \hline \text { B } & {\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}} & \text { Q } & \mathrm{sp}^3, \quad \mu=2.84 \mathrm{BM} \\ \hline \text { C } & {\left[\mathrm{Ni}(\mathrm{Cl})_4\right]^{2-}} & \text { R } & \mathrm{sp}^3, \quad \mu=0 \\ \hline \text { D } & {[\mathrm{MnBr}]^{2-}} & \text { S } & \mathrm{dsp}^2, \quad \mu=0 \\ \hline \end{array}\)

An unsaturated hydrocarbon \([\mathrm{A}]\) undergoes the following series of reactions. Identify \([\mathrm{A}]\).

The mass of hydrogen in gram required to completely saturate 1 mole of triolein is

Liquor ammonia bottles are opened only after cooling. This is because

5.0 moles of an Ideal gas at 3.0 atm pressure and \(27^{\circ} \mathrm{C}\) is compressed isothermally to half its volume by application of an external pressure of \(3.5 \mathrm{~atm}\). What is the amount of work done (in joules) on the gas?
Given: \(1 \mathrm{~L} \mathrm{~atm}=101.3 \mathrm{~J}: \mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}\)

The place \(x-2 y+z=0\) is parallel to the line

A wire of negligible mass having uniform area of cross section 'A' and young modulus ' Y ' is used to suspend a point mass ' m '. The point mass executes simple harmonic motion in a vertical plane with a period ' T ', then the length of the wire is :

The remainder obtained when \((1 !)^{2}+(2 !)^{2}+(3 !)^{2}+\ldots+(100 !)^{2}\) is divided by \(10^{2}\) is

If \(
\left[\begin{array}{lll}
1 & x & 1
\end{array}\right]\left[\begin{array}{ccc}
1 & 3 & 2 \\
2 & 5 & 1 \\
15 & 3 & 2
\end{array}\right]\left[\begin{array}{l}
1 \\
2 \\
x
\end{array}\right]=[0]
\) then x is equal to

The solution of \(\left(2 x-10 y^{3}\right) \frac{d y}{d x}+y=0\) is

The number of common tangents to the circles \(x^{2}+y^{2}-2 x-4 y+1=0\) and \(x^{2}+y^{2}-12 x-16 y+91=0\) is