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COMEDK · Chemistry · 24. Coordination Compounds

Based on Crystal Field theory, match the Complex ions listed in Column I with the electronic configuration in the d orbitals of the central metal ion listed in Column II.

No.ComplexNo.d orbital configuration of central metal ion
A\([Mn(CN)_6]^{4-}\)P\(e_g^2 t_{2g}^3\)
B\([Co(H_2O)_6]^{2+}\)Q\(t_{2g}^4 e_g^2\)
C\([Fe(H_2O)_6]^{2+}\)R\(t_{2g}^5\)
D\([MnCl_4]^{2-}\)S\(t_{2g}^5 e_g^2\)

  1. A \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}\)
  2. B \(\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q}\)
  3. C \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{Q}\)
  4. D \(\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{R}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}\)

Step-by-step Solution

Detailed explanation

For \(\left[Mn(CN)_6\right]^{4-}\), the oxidation state of \(Mn\) is \(+2\). The electronic configuration of \(Mn^{2+}\) is \(3d^5\). Since \(CN^{-}\) is a strong field ligand, pairing occurs. The configuration is \(t_{2g}^5 e_g^0\), which is represented by (R). For…