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COMEDK · Chemistry · 8. Ionic Equilibrium

At 30°C the solubility of PbI\(_2\) salt in 0.2 M KI solution will be X, if the solubility product of PbI\(_2\) at 30°C is \(2.4 \times 10^{-8}\). Identify the value of X.

  1. A \(6.0 \times 10^{-7}\)M
  2. B \(2.4 \times 10^{-8}\)M
  3. C \(3.0 \times 10^{-8}\)M
  4. D \(4.8 \times 10^{-7}\)M
Verified Solution

Answer & Solution

Correct Answer

(A) \(6.0 \times 10^{-7}\)M

Step-by-step Solution

Detailed explanation

The dissociation of \(PbI_2\) is given by: \(PbI_2(s) \rightleftharpoons Pb^{2+}(aq) + 2I^-(aq)\) Let the solubility of \(PbI_2\) in \(0.2\) M \(KI\) solution be \(s\). The concentration of \(I^-\) ions from \(KI\) is \(0.2\) M. Since \(KI\) is a strong electrolyte, it…