COMEDK · Chemistry · 18. Electrochemistry
Arrange the following redox couples in the increasing order of their reducing strength:
\(\begin{array}{ll}
{[\mathrm{A}]=\mathrm{Cu} / \mathrm{Cu}^{2+}} & \mathrm{E}^0=-0.34 \mathrm{~V} \\
{[\mathrm{~B}]=\mathrm{Ag} / \mathrm{Ag}^{+}} & \mathrm{E}^0=-0.8 \mathrm{~V} \\
{[\mathrm{C}]=\mathrm{Ca} / \mathrm{Ca}^{2+}} & \mathrm{E}^0=+2.87 \mathrm{~V} \\
{[\mathrm{D}]=\mathrm{Cr} / \mathrm{Cr}^{3+}} & \mathrm{E}^0=+0.74 \mathrm{~V}
\end{array}\)
- A B < A < D < C
- B D < A < C < B
- C A < C < B < D
- D C < D < A < B
Answer & Solution
Correct Answer
(A) B < A < D < C
Step-by-step Solution
Detailed explanation
The reducing strength of a species is determined by its standard oxidation potential. A higher standard oxidation potential (\(E^{0}_{ox}\)) indicates a stronger reducing agent. The given values are standard oxidation potentials (\(E^{0}_{ox}\)) for the couples \(M/M^{n+}\). The…
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