COMEDK · Chemistry · 24. Coordination Compounds
Arrange the following compounds in the decreasing order of the molar conductivities of their aqueous solutions.
\(\begin{array}{cccc}\mathrm{A} & \quad \mathrm{B} & \quad \mathrm{C} & \quad \mathrm{D} \\ {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}] \mathrm{Cl}_2\right.} & \quad {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right]} & \quad {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}} & \quad {\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_3}\end{array}\)
- A \(\mathrm{B}>\mathrm{A}>\mathrm{C}>\mathrm{D}\)
- B \(\mathrm{B}>\mathrm{C}>\mathrm{A}>\mathrm{D}\)
- C \(D>A>C>B\)
- D \(\mathrm{A}>\mathrm{B}>\mathrm{D}>\mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(D>A>C>B\)
Step-by-step Solution
Detailed explanation
Molar conductivity of an electrolyte in aqueous solution depends on the number of ions produced upon dissociation. The greater the number of ions, the higher the molar conductivity. Dissociation of the given complexes: A:…
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