COMEDK · Chemistry · 24. Coordination Compounds
Arrange the complex ions in the increasing order of their magnetic moments
A. \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
B. \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\)
C. \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}\)
D. \(\left[\mathrm{FeF}_6\right]^{3-}\)
- A \(\mathrm{B} <\mathrm{C} <\mathrm{A} <\mathrm{D}\)
- B \(\mathrm{A} <\mathrm{D} <\mathrm{C} <\mathrm{B}\)
- C \(\mathrm{D} <\mathrm{A} <\mathrm{B} <\mathrm{C}\)
- D \(\mathrm{D} <\mathrm{C} <\mathrm{B} <\mathrm{A}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{B} <\mathrm{C} <\mathrm{A} <\mathrm{D}\)
Step-by-step Solution
Detailed explanation
The magnetic moment is calculated using the formula \(\mu = \sqrt{n(n+2)}\) B.M., where \(n\) is the number of unpaired electrons. A. In \(\left[\mathrm{Fe}(\mathrm{H}_2\mathrm{O})_6\right]^{2+}\), Fe is in \(+2\) oxidation state (\(3d^6\)). \(\mathrm{H}_2\mathrm{O}\) is a weak…
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