COMEDK · Chemistry · 26. Alcohols Phenols and Ethers
An organic compound \([\mathrm{A}]\left(\mathrm{C}_5 \mathrm{H}_{12} \mathrm{O}\right)\), on reaction with conc. \(\mathrm{H}_2 \mathrm{SO}_4\) at \(443 \mathrm{~K}\) gives \([\mathrm{B}]\) as one of the products. Compound [B] undergoes further reaction with \(\mathrm{O}_3\) and \(\mathrm{Zn} / \mathrm{H}_2 \mathrm{O}\) to give Propanone and Ethanal as products. Identify compound [A]
- A Pentan-2-ol
- B Pentan-1-ol
- C 2- Methylbutan-1-ol
- D 3-Methylbutan-2-ol
Answer & Solution
Correct Answer
(D) 3-Methylbutan-2-ol
Step-by-step Solution
Detailed explanation
The molecular formula of compound [A] is \(C_5H_{12}O\), which corresponds to a saturated alcohol or ether. Since it reacts with conc. \(H_2SO_4\) at \(443 K\) to form an alkene [B], [A] is an alcohol. The reaction of [B] with \(O_3\) followed by \(Zn/H_2O\) (reductive…
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