COMEDK · Chemistry · 7. Chemical Equilibrium
An equilibrium mixture taken in 2litre vessel of the reaction: \(2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g)\) has 4 moles of \(\text{SO}_2\), 3moles of \(\text{O}_2\) and 6moles of \(\text{SO}_3\) then the value of equilibrium constant \((K_c)\) will be:
- A 0.75 L mol\(^{-1}\)
- B 0.15 mol L\(^{-1}\)
- C 1.5 L mol\(^{-1}\)
- D 15 mol L\(^{-1}\)
Answer & Solution
Correct Answer
(C) 1.5 L mol\(^{-1}\)
Step-by-step Solution
Detailed explanation
The given equilibrium reaction is: \(2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g)\) The volume of the vessel is \(V = 2\) L. The equilibrium concentrations of the gases are: \([\text{SO}_2] = \dfrac{4}{2} = 2 \text{ mol L}^{-1}\)…
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