COMEDK · Chemistry · 18. Electrochemistry
An electric current is passed through silver and water voltameters connected in series. The cathode of the silver voltameter weighed \(0.054 \mathrm{~g}\) more at the end of electrolysis. The volume of \(\mathrm{O}_{2}\) evolved at the anode of water voltameter is
- A \(5.6 \mathrm{~cm}^{3}\)
- B \(11.2 \mathrm{~cm}^{3}\)
- C \(224 \mathrm{~cm}^{3}\)
- D \(2.8 \mathrm{~cm}^{3}\)
Answer & Solution
Correct Answer
(D) \(2.8 \mathrm{~cm}^{3}\)
Step-by-step Solution
Detailed explanation
According to Faraday second law, \(\frac{W_{\mathrm{Ag}}}{W_{\mathrm{O}_{2}}}=\frac{E_{\mathrm{Ag}}}{E_{\mathrm{O}_{2}}}\) \(\frac{0.054}{W_{\mathrm{O}_{2}}}=\frac{108}{8}\) \(W_{\mathrm{O}_{2}}=\frac{0.054}{108} \times 8=4 \times 10^{-3} \mathrm{~g}\)…
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