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COMEDK · Chemistry · 17. Solutions

An aqueous solution of an electrolyte \(\text{A}_3\text{B}\) is prepared by dissolving 0.5625 moles in 750 ml of water and is found to be 80% ionised. If \(\text{K}_\text{b}\) for water is \(0.52\text{ K kg mol}^{-1}\), calculate the boiling point of the solution at 1.0 atm pressure.
(Assume the boiling point of pure water is 373 K).

  1. A 373.18 K
  2. B 371.68 K
  3. C 374.33 K
  4. D 377.2 K
Verified Solution

Answer & Solution

Correct Answer

(C) 374.33 K

Step-by-step Solution

Detailed explanation

Molality: \(m = \dfrac{0.5625}{0.75} = 0.75\) m \(A_3B\) dissociates into 4 ions, \(n = 4\), \(\alpha = 0.8\) Van't Hoff factor: \(i = 1 + (n-1)\alpha = 1 + 3 \times 0.8 = 3.4\) \(\Delta T_b = i \cdot K_b \cdot m = 3.4 \times 0.52 \times 0.75 = 1.326\) K…
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