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COMEDK · Chemistry · 14. Hydrocarbons

Ammoniacal silver nitrate forms a white precipitate easily with

  1. A \(\mathrm{CH}_3 \mathrm{C}=\mathrm{CH}\)
  2. B \(\mathrm{CH}_3 \mathrm{C}=\mathrm{CCH}_3\)
  3. C \(\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}_2\)
  4. D \(\mathrm{CH}_2=\mathrm{CH}_2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{CH}_3 \mathrm{C}=\mathrm{CH}\)

Step-by-step Solution

Detailed explanation

In general, \(\mathrm{C}_2 \mathrm{H}_2\) and all 1-alkynes given white precipitate with ammoniacal silver nitrate. Thus, in this question, propyne-1 \(\left(\mathrm{CH}_3 \mathrm{C}=\mathrm{CH}\right)\) will give white precipitate with ammoniacal silver nitrate.