COMEDK · Chemistry · 17. Solutions
A non-volatile solute A weighing 60 g when dissolved in 212 g of the solvent Xylene reduces its vapour pressure to \(60 \%\). What is the Molar mass of A in \(\mathrm{g} / \mathrm{mol}\) ? [MM of xylene \(=106 \mathrm{~g} / \mathrm{mol}\) ]
- A \(56\)
- B \(60\)
- C \(126\)
- D \(45\)
Answer & Solution
Correct Answer
(D) \(45\)
Step-by-step Solution
Detailed explanation
According to Raoult's law for a non-volatile solute, the relative lowering of vapour pressure is equal to the mole fraction of the solute: \(\dfrac{P^o - P_s}{P^o} = \dfrac{n_A}{n_A + n_X}\) Given that the vapour pressure is reduced to \(60\%\), we have \(P_s = 0.6 P^o\).…
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