COMEDK · Chemistry · 19. Chemical Kinetics
A given chemical reaction is represented by the following stoichiometric equation.
\(3 X+2 Y+\dfrac{5}{2} Z \rightarrow P_1+P_2+P_3\)
The rate of reaction can be expressed as _________.
- A \(\left(\dfrac{d[X]}{d t}\right)=\dfrac{3}{2}\left(\dfrac{d[Y]}{d t}\right)=\dfrac{15}{4}\left(\dfrac{d[Z]}{d t}\right)\)
- B \(\dfrac{2}{3}\left(\dfrac{d[X]}{d t}\right)=\left(\dfrac{d[Y]}{d t}\right)=\dfrac{4}{5}\left(\dfrac{d[Z]}{d t}\right)\)
- C \(\dfrac{4}{15}\left(\dfrac{d[X]}{d t}\right)=\dfrac{4}{5}\left(\dfrac{d[Y]}{d t}\right)=\dfrac{8}{15}\left(\dfrac{d[Z]}{d t}\right)\)
- D \(\dfrac{3}{2}\left(\dfrac{d[X]}{d t}\right)=\dfrac{1}{4}\left(\dfrac{d[Y]}{d t}\right)=\dfrac{8}{5}\left(\dfrac{d[Z]}{d t}\right)\)
Answer & Solution
Correct Answer
(B) \(\dfrac{2}{3}\left(\dfrac{d[X]}{d t}\right)=\left(\dfrac{d[Y]}{d t}\right)=\dfrac{4}{5}\left(\dfrac{d[Z]}{d t}\right)\)
Step-by-step Solution
Detailed explanation
For a general reaction \(aA + bB + cC \rightarrow Products\), the rate of reaction is given by: Rate \(= -\dfrac{1}{a} \dfrac{d[A]}{dt} = -\dfrac{1}{b} \dfrac{d[B]}{dt} = -\dfrac{1}{c} \dfrac{d[C]}{dt}\) Given the reaction \(3X + 2Y + \dfrac{5}{2}Z \rightarrow P_1 + P_2 + P_3\),…
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