COMEDK · Chemistry · 18. Electrochemistry
A galvanic cell is constructed using the redox reaction,
\(\frac{1}{2} \mathrm{H}_{2}(g)+\operatorname{AgCl}(s) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{Cl}^{-}(a q)+\operatorname{Ag}(s)\)
it is represented as
- A \(\mathrm{Pt}\left|\mathrm{H}_{2}(g)\right| \mathrm{HCl}(\mathrm{sol})|| \mathrm{AgNO}_{3}(\mathrm{sol}) \mid \mathrm{Ag}\)
- B \(\operatorname{Ag}|\operatorname{AgCl}(s)| \mathrm{KCl}(\mathrm{sol})|| \mathrm{HCl}(\mathrm{sol}), \mathrm{H}_{2}(\mathrm{~g}) \mid \mathrm{Pt}\)
- C \(\mathrm{Pt}\left|\mathrm{H}_{2}(g)\right| \mathrm{KCl}(\operatorname{sol}) \| \operatorname{AgCl}(s) \mid \mathrm{Ag}\)
- D \(\mathrm{Pt}\left|\mathrm{H}_{2}(g), \mathrm{HCl}(\operatorname{sol})\right||\operatorname{AgCl}(s)| \mathrm{Ag}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{Pt}\left|\mathrm{H}_{2}(g), \mathrm{HCl}(\operatorname{sol})\right||\operatorname{AgCl}(s)| \mathrm{Ag}\)
Step-by-step Solution
Detailed explanation
At anode, oxidation occurs of \(\mathrm{H}_{2}\) (gas), while at cathode reduction of \(\mathrm{AgCl}\) take place. \(\therefore\) The cell notation is \(\mathrm{Pt}\left|\mathrm{H}_{2}(\mathrm{~g}), \mathrm{HCl}(\mathrm{sol}) \| \mathrm{AgCl}(s)\right| \mathrm{Ag}\)
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