COMEDK · Chemistry · 19. Chemical Kinetics
A first order reaction proceeds to \(90 \%\) completion. What will be the approximate time taken for \(90 \%\) completion in relation to \(t_{1 / 2}\) of the reaction?
- A 5.66 times of \(\mathrm{t}_{1 / 2}\)
- B 5.02 times of \(\mathrm{t}_{1 / 2}\)
- C 4.54 times of \(\mathrm{t}_{1 / 2}\)
- D 3.32 times of \(\mathrm{t}_{1 / 2}\)
Answer & Solution
Correct Answer
(D) 3.32 times of \(\mathrm{t}_{1 / 2}\)
Step-by-step Solution
Detailed explanation
For a first order reaction, the rate constant \(k\) is given by \(k = \dfrac{2.303}{t} \log \left( \dfrac{[A]_0}{[A]_t} \right)\). For \(90 \%\) completion, \([A]_t = [A]_0 - 0.90[A]_0 = 0.10[A]_0\). Substituting this into the rate equation,…
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