COMEDK · Chemistry · 18. Electrochemistry
A current of 2.5 amperes is passed through 800 ml of 0.48 M solution of \(\mathrm{CuSO}_4\) for 1.0 hour with a current efficiency of \(80 \%\). If the volume of the solution remains unchanged, what is the final molarity of the solution?
- A \(0.298\)
- B \(0.433\)
- C \(0.315\)
- D \(0.386\)
Answer & Solution
Correct Answer
(B) \(0.433\)
Step-by-step Solution
Detailed explanation
The reaction at the cathode is \(\text{Cu}^{2+} + 2e^{-} \rightarrow \text{Cu}(s)\). The total charge passed through the solution is \(Q = I \times t \times \text{efficiency} = 2.5 \text{ A} \times (1.0 \times 3600 \text{ s}) \times 0.80 = 7200 \text{ C}\). The number of moles…
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