COMEDK · Chemistry · 18. Electrochemistry

A current of 0.10 A was passed for 2 hours through a dilute solution of sulphuric acid. The total volume of gaseous products produced at STP is:
[Given: \(1 \mathrm{~F}=96500 \mathrm{C}\); Molar volume at STP is \(22.7 \mathrm{~mol}^{-1}\) ]

A 150 mL
B 115 mL
C 127 mL
D 139 mL

Verified Solution

Answer & Solution

Correct Answer

(C) 127 mL

Step-by-step Solution

Detailed explanation

The electrolysis of dilute sulphuric acid involves the electrolysis of water. The reactions at the electrodes are as follows: At cathode: \(4H^{+}(aq) + 4e^{-} \rightarrow 2H_{2}(g)\) At anode: \(2H_{2}O(l) \rightarrow O_{2}(g) + 4H^{+}(aq) + 4e^{-}\) The total charge passed…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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A current of 0.10 A was passed for 2 hours through a dilute solution of sulphuric acid. The total volume of gaseous products produced at STP is:[Given: \(1 \mathrm{~F}=96500 \mathrm{C}\); Molar volume at STP is \(22.7 \mathrm{~mol}^{-1}\) ]

Step-by-step Solution

A current of 0.10 A was passed for 2 hours through a dilute solution of sulphuric acid. The total volume of gaseous products produced at STP is:
[Given: \(1 \mathrm{~F}=96500 \mathrm{C}\); Molar volume at STP is \(22.7 \mathrm{~mol}^{-1}\) ]