COMEDK · Chemistry · 2. Structure of Atom
A body of mass \(10 \mathrm{mg}\) is moving with a velocity of \(100 \mathrm{~ms}^{-1}\). The wavelength of de-Broglie wave associated with it would be
( \(\left.h=6.63 \times 10^{-34} \mathrm{Js}\right)\)
- A \(6.63 \times 10^{-37} \mathrm{~m}\)
- B \(6.63 \times 10^{-31} \mathrm{~m}\)
- C \(6.63 \times 10^{-34} \mathrm{~m}\)
- D \(6.63 \times 10^{-35} \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(6.63 \times 10^{-34} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
\(m=10 \mathrm{mg}, v=100 \mathrm{~ms}^{-1}, \lambda=\) ? de-Broglie wavelength, \(\lambda=\frac{h}{m v}\) \[ \begin{aligned} &=\frac{6.63 \times 10^{-34}}{10 \times 10^{-3} \times 100} \\ &=6.63 \times 10^{-34} \mathrm{~m} \end{aligned} \]
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