COMEDK · Chemistry · 2. Structure of Atom
A 150 watt bulb emits light of wavelength \(6600 Å\) and only \(8 \%\) of the energy is emitted as light. How many photons are emitted by the bulb per second?
- A \(4 \times 10^{19}\)
- B \(3.24 \times 10^{19}\)
- C \(4.23 \times 10^{20}\)
- D \(3 \times 10^{20}\)
Answer & Solution
Correct Answer
(A) \(4 \times 10^{19}\)
Step-by-step Solution
Detailed explanation
Power of the bulb \(=150 \mathrm{~W}=150 \mathrm{~J} \mathrm{~s}^{-1}\) As only \(8 \%\) of the energy is emitted as light so, the total energy emitted per second \[ =\frac{150 \mathrm{~J} \times 8}{100}=12 \mathrm{~J} \] Energy of one photon, \(E=h v=\frac{h c}{\lambda}\)…
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