COMEDK · Chemistry · 9. Redox Reactions
50 ec of oxalic acid is oxidised by 25 cc of \(0.20 \mathrm{~N} \mathrm{KMnO}\). The mass of oxalic acid present in 500 ce of the solution is
- A \(3.15 \mathrm{~g}\)
- B \(31.5 \mathrm{~g}\)
- C \(6.3 \mathrm{~g}\)
- D \(63 \mathrm{~g}\)
Answer & Solution
Correct Answer
(A) \(3.15 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
Equivalent moles of oxalic acid = Equivalent moles \(=N_{1} V_{1}=25 \times 0.2 \times 10^{-3}=5 \times 10^{-3}=0.005\) \(\frac{\text { Weight of oxalic acid }}{\text { Eq. weight of oxalic acid }}=0.005\) Weight of oxalic acid \(=0.05 \times 63=0.315 \mathrm{~g}\)…
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