COMEDK · Chemistry · 18. Electrochemistry
3 Faraday of electricity is passed through three electrolytic cells connected in series containing \(\mathrm{Ag}^{+}, \mathrm{Ca}^{2+}\) and \(\mathrm{Al}^{+3}\) ions respectively. The molar ratio in which the 3 metal ions are liberated at the electrodes is
- A \(3: 2: 1\)
- B \(1:2:3\)
- C \(6: 3: 2\)
- D \(4: 4: 2\)
Answer & Solution
Correct Answer
(C) \(6: 3: 2\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{r}\mathrm{Ag}^{+}+e^{-} \longrightarrow \mathrm{Ag} \\ \mathrm{Ca}^{+2}+2 e^{-} \longrightarrow \mathrm{Ca} \\ \mathrm{Al}^{+3}+3 e^{-} \longrightarrow \mathrm{Al}\end{array}\) For 1 mol of \(\mathrm{Ag}^{+}, \mathrm{Ca}^{+2}\) and…
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