AP EAMCET · PHYSICS · Mechanical Properties of Solids
When a sphere is taken to the bottom of a sea of depth 1 km, it contracts in volume by \(0.01 \%\), then the bulk modulus of the material of the sphere is (Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A \(10 \times 10^6 \mathrm{~N} \mathrm{~m}^{-2}\)
- B \(1.2 \times 10^{10} \mathrm{~N} \mathrm{~m}^{-2}\)
- C \(10 \times 10^{10} \mathrm{~N} \mathrm{~m}^{-2}\)
- D \(10 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}\)
Answer & Solution
Correct Answer
(C) \(10 \times 10^{10} \mathrm{~N} \mathrm{~m}^{-2}\)
Step-by-step Solution
Detailed explanation
\(\Delta P = \rho g h = (1000 \mathrm{~kg} \mathrm{~m}^{-3})(10 \mathrm{~m} \mathrm{~s}^{-2})(1000 \mathrm{~m}) = 10^7 \mathrm{~N} \mathrm{~m}^{-2}\)…
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