AP EAMCET · PHYSICS · Electrostatics
Three particles of each charge \(q\) are placed at the vertices of an equilateral triangle of side \(L\). The work to be done to decrease the side of the triangle to \(\frac{L}{2}\) is
- A \(\frac{1}{4 \pi \varepsilon_0} \frac{\mathrm{q}^2}{\mathrm{~L}}\)
- B \(\frac{1}{4 \pi \varepsilon_0} \frac{2 q^2}{L}\)
- C \(\frac{1}{4 \pi \varepsilon_0} \frac{3 q^2}{L}\)
- D \(\frac{1}{4 \pi \varepsilon_0} \frac{3 q^2}{2 L}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{4 \pi \varepsilon_0} \frac{3 q^2}{L}\)
Step-by-step Solution
Detailed explanation
\(W = U_f - U_i\) \(W = 3 \left(\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{L/2}\right) - 3 \left(\frac{1}{4 \pi \varepsilon_0} \frac{q^2}{L}\right)\) \(W = \frac{3 q^2}{4 \pi \varepsilon_0} \left(\frac{2}{L} - \frac{1}{L}\right)\)…
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