AP EAMCET · PHYSICS · Kinetic Theory of Gases
Three closed vessels \(A, B\) and \(C\) are at the same temperature \(T\) and contain gases. Vessel \(A\) contains only \(\mathrm{O}_2, B\) contains only \(\mathrm{N}_2\) and \(\mathrm{C}\) contains a mixture of equal quantities of \(\mathrm{O}_2\) and \(\mathrm{N}_2\). If the rms speed of \(\mathrm{O}_2\) molecules in vessel \(A\) is \(v_1\) and that of \(\mathrm{N}_2\) molecules in vessel \(B\) is \(v_2\) then the rms speed of \(\mathrm{O}_2\) molecules in vessel \(\mathrm{C}\) is
- A \(\left(\frac{v_1+v_2}{2}\right)\)
- B \(v_1\)
- C \(\left(v_1 v_2\right)\)
- D \(\frac{v_1}{2}\)
Answer & Solution
Correct Answer
(B) \(v_1\)
Step-by-step Solution
Detailed explanation
Key Idea Root mean square velocity of any gas is given by \(v_{\mathrm{rms}}=\sqrt{\frac{3 R T}{M}}\) Where, \(M=\) molecular weight. As, rms speed of any gas is depends on the temperature of gas and molecular weight of gas. In a mixture of gases (say \(\mathrm{N}_2\) and…
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