AP EAMCET · PHYSICS · Electrostatics
The electric field intensity (E) at a distance of 3 m from a uniform long straight wire of linear charge density 0.2 m \(\mathrm{Cm}^{-1}\) is
- A \(1.2 \times 10^3 \mathrm{Vm}^{-1}\)
- B \(0.6 \times 10^3 \mathrm{Vm}^{-1}\)
- C \(1.8 \times 10^3 \mathrm{Vm}^{-1}\)
- D \(2.4 \times 10^3 \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.2 \times 10^3 \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
The electric field at a distance r from a uniform straight wire is \(\begin{aligned} & \mathrm{E}=\frac{2 \mathrm{k} \lambda}{\mathrm{r}}=\frac{2 \times 9 \times 10^9 \times 0.2 \times 10^{-6}}{3} \\ & =1.2 \times 10^3 \mathrm{Vm}^{-1} \end{aligned}\)
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