AP EAMCET · PHYSICS · Waves and Sound
Small amplitude progressive wave in a stretched string has a speed of \(100 \mathrm{cms}^{-1}\), and frequency \(100 \mathrm{~Hz}\). The phase difference between two points \(2.75 \mathrm{~cm}\) apart on the string, in radians, is
- A 0
- B \(11 \frac{\pi}{2}\)
- C \(\frac{\pi}{4}\)
- D \(\frac{3 \pi}{8}\)
Answer & Solution
Correct Answer
(B) \(11 \frac{\pi}{2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given; } \mathrm{f}=100 \mathrm{~Hz}, \mathrm{v}=100 \mathrm{~cm} \mathrm{~s}^{-1}=1 \mathrm{~ms}^{-1}, \\ & \Delta \mathrm{x}=2.75 \mathrm{~cm}=2.75 \times 10^{-2} \mathrm{~m}, \text { Phase difference } \\ & \Delta \phi=? \\ & \Delta \phi=\frac{2…
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