AP EAMCET · PHYSICS · Thermodynamics
Match of the following.
\(\begin{array}{ll}
\hline \text{ Column I } & \text{ Column II } \\
\hline \begin{array}{ll}
\text{A. Ratio of } \frac{\Delta Q}{\Delta U} \text{ in an isobaric} \\
\text{process}
\end{array} & 1. \frac{T_1}{\left(T_1-T_2\right)} \\
\hline \begin{array}{ll}
\text{B. Ratio of } \frac{\Delta Q}{\Delta W} \text{ in an isobaric} \\
\text{process}
\end{array} & 2. \frac{T_2}{\left(T_1-T_2\right)} \\
\hline \begin{array}{l}
\text{C. Coefficient of performance} \\
\text{of a refrigerator}
\end{array} & 3. \frac{\gamma}{\gamma-1} \\
\hline \begin{array}{l}
\text{D. Coefficient of performance} \\
\text{of a heat pump}
\end{array} & 4. \gamma \\
\hline
\end{array}\)
Codes
\(\begin{array}{llll}A & B & C & D\end{array}\)
- A \(\begin{array}{llll}4 & 3 & 2 & 1\end{array}\)
- B \(\begin{array}{llll}2 & 1 & 4 & 3\end{array}\)
- C \(\begin{array}{llll}3 & 1 & 2 & 4\end{array}\)
- D \(\begin{array}{llll}4 & 2 & 3 & 1\end{array}\)
Answer & Solution
Correct Answer
(A) \(\begin{array}{llll}4 & 3 & 2 & 1\end{array}\)
Step-by-step Solution
Detailed explanation
We know that, at constant volume, Heat supplied, \(\Delta Q_1=\Delta U=C_V \Delta T\) At constant pressure, heat supplied, \(\Delta Q=C_p \Delta T=\Delta U+\Delta W\) Ratio of heat capacity at constant pressure to constant volume is \(\gamma=\frac{C_p}{C_V}\) Now,…
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