AP EAMCET · PHYSICS · Magnetic Effects of Current
Magnetic field at the centre of a circular loop of area \(A\) is \(B\). Then the magnetic moment of the loop is
(\(\mu_0\)-permeability of the free space)
- A \(\frac{B A^2}{\mu_0 \pi}\)
- B \(\frac{B A \sqrt{A}}{\mu_0}\)
- C \(\frac{B A \sqrt{A}}{\mu_0 \pi}\)
- D \(\frac{2 B A \sqrt{A}}{\mu_0 \sqrt{\pi}}\)
Answer & Solution
Correct Answer
(D) \(\frac{2 B A \sqrt{A}}{\mu_0 \sqrt{\pi}}\)
Step-by-step Solution
Detailed explanation
As we know, the magnetic field due to a current carrying circular loop at the centre, \(B=\frac{\mu_0 i}{2 R}\) ...(i) So, the magnetic moment of the Loop, \(M=i A\) From Eq. (i), we get…
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