AP EAMCET · PHYSICS · Atomic Physics
In hydrogen atom, if an electron in the orbit with principal quantum number ' \(n\) ' jumps to the first excited state, the wavelength of the emitted photon is ' \(\lambda\) '. Then the value of \(\mathrm{n}\) is
(R-Rydberg constant)
- A \(\sqrt{\frac{4 \lambda R}{\lambda R+4}}\)
- B \(\sqrt{\frac{4 \lambda R}{\lambda R-4}}\)
- C \(\sqrt{\frac{\lambda \mathrm{R}-4}{4 \lambda \mathrm{R}}}\)
- D \(\sqrt{\frac{\lambda \mathrm{R}+4}{4 \lambda \mathrm{R}}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{4 \lambda R}{\lambda R-4}}\)
Step-by-step Solution
Detailed explanation
(When electron jump from \(\mathrm{n}_2=\mathrm{n}\) to first excited state…
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