AP EAMCET · PHYSICS · Alternating Current
An inductor and a resistor of \(25 \Omega\) are connected in series to an ac source of voltage \(100 \sin (100 \pi \mathrm{t})\) volt. If the impedance of the circuit is \(50 \Omega\), the average power dissipated per cycle in the circuit is
- A \(10 \mathrm{~W}\)
- B \(25 \mathrm{~W}\)
- C \(50 \mathrm{~W}\)
- D \(100 \mathrm{~W}\)
Answer & Solution
Correct Answer
(D) \(100 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
The average power dissipated per cycle in the circuit \(\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{Z}^2} \mathrm{R}=\frac{100^2}{50^2} \times 25=100 \mathrm{~W}\)
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