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AP EAMCET · PHYSICS · Magnetic Effects of Current

A velocity selector is to be constructed to select ions with a velocity of \(6 \mathrm{~km} \mathrm{~s}^{-1}\).
If the electric field used is \(400 \mathrm{~V} \mathrm{~m}^{-1}\), then the magnetic field to be used is

  1. A \(\frac{11}{20} \mathrm{~T}\)
  2. B \(\frac{2}{3} \mathrm{~T}\)
  3. C \(\frac{1}{15} \mathrm{~T}\)
  4. D \(\frac{2}{15} \mathrm{~T}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{15} \mathrm{~T}\)

Step-by-step Solution

Detailed explanation

\(B = \frac{E}{v}\) \(B = \frac{400 \mathrm{~V} \mathrm{~m}^{-1}}{6 \times 10^3 \mathrm{~m} \mathrm{~s}^{-1}}\) \(B = \frac{1}{15} \mathrm{~T}\)