AP EAMCET · PHYSICS · Motion In One Dimension
A stone falls freely such that the distance covered by it in the last second of its motion is equal to the distance covered by it in the first \(5 \mathrm{~s}\). It is in air for....... \(\mathrm{s}\).
- A 12
- B 13
- C 25
- D 26
Answer & Solution
Correct Answer
(B) 13
Step-by-step Solution
Detailed explanation
Since, stone falls freely, hence its initial velocity, \(u=0\) Distance covered by the stone in first \(5 \mathrm{~s}\) is given as \(\begin{aligned} h_1 & =u t+\frac{1}{2} g t^2=0 \times 5+\frac{1}{2} \times 9.8 \times 5^2 \\ & =122.5 \mathrm{~m} \end{aligned}\) Since, distance…
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