AP EAMCET · PHYSICS · Mechanical Properties of Solids
A steel wire of length \(1.25 \mathrm{~m}\) is stretched between two rigid supports. The tension in the wire produces an elastic strain of \(0.14 \%\). The fundamental frequency of the wire is (Density and Young's modulus of steel are \(7.7 \times 10^3 \mathrm{kgm}^{-3}\) and \(2.2 \times 10^{11} \mathrm{Nm}^{-2}\) respectively)
- A \(20 \mathrm{~Hz}\)
- B \(40 \mathrm{~Hz}\)
- C \(80 \mathrm{~Hz}\)
- D \(160 \mathrm{~Hz}\)
Answer & Solution
Correct Answer
(C) \(80 \mathrm{~Hz}\)
Step-by-step Solution
Detailed explanation
Given, length of wire \(=1.25 \mathrm{~m}\) strain produced \(=0.14 \%\) density of wire, \(d=7.7 \times 10^3 \mathrm{kgm}^{-3}\) young's modulus, \(Y=2.2 \times 10^{11} \mathrm{Nm}^{-2}\) Fundamental frequency of vibration over a string is given by…
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