AP EAMCET · PHYSICS · Waves and Sound
A sound wave of frequency 500 Hz travels between two points X and Y separated by a distance of 600 m in a time of 2 s. The number of waves between the points X and Y are
- A \(1000\)
- B \(1500\)
- C \(300\)
- D \(600\)
Answer & Solution
Correct Answer
(A) \(1000\)
Step-by-step Solution
Detailed explanation
\(v = \frac{d}{t} = \frac{600 \text{ m}}{2 \text{ s}} = 300 \text{ m/s}\) \(\lambda = \frac{v}{f} = \frac{300 \text{ m/s}}{500 \text{ Hz}} = 0.6 \text{ m}\) \(n = \frac{d}{\lambda} = \frac{600 \text{ m}}{0.6 \text{ m}} = 1000\)
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